WebIn the Tables section, select the table, such as CN_TP_TRANSACTIONS_ALL. In the Columns section row for the column that you want to enable: In the User Name field, enter a display name, such as Area Code for the column AREA_CODE. Each column that you enable for processing must have a corresponding user name because the user name appears in the ... WebOct 28, 2024 · All_tables: If the user does not have access or privilege to view the dba_tables it can still get a list of all the tables that it has access to using the following SQL query. This SQL query gives the list of tables that can be accessed by the user along with its owner. Query: SELECT owner, table_name FROM all_tables;
How to List All Tables in Oracle? - GeeksforGeeks
WebApr 19, 2016 · A table with two columns: one with the name of the table and the other one with all the colums in that table. Thank you. For instance: TABLE_NAME COLUMNS … WebFA_DISTRIBUTION_HISTORY contains information about the employee, location, and Accounting Flexfield values you assign to your assets. The depreciation program uses this information to allocate depreciation expense and the Transfers form uses it to maintain an audit trail of asset transfers. . When you initially assign distributions to an asset ... blue freshwater lobster
ALL_TAB_COLUMNS - Oracle Help Center
WebIn Oracle, ALL_TABLES, DBA _TABLES and USER_TABLES have the same columns, except that USER_TABLES does not contain owner column. All Tables in the Specified Schema (Database in SQL Server) In Oracle, you can use the following query to select all tables in the specified schema: Oracle : WebJul 10, 2024 · ALL_TAB_COLUMNS and ALL_TAB_COLS are the views in Oracle that describes the columns of the tables, views, and clusters accessible to the current user. The only difference between two views is, ALL_TAB_COLS won’t filter hidden columns where as ALL_TAB_COLUMNS filters the hidden columns. WebFor example, you can generate a list of all column names for a table by querying the ALL_TAB_COLUMNS view. Something like this should work: SELECT LISTAGG (COLUMN_NAME, ', ') WITHIN GROUP (ORDER BY COLUMN_ID) from ALL_TAB_COLUMNS WHERE OWNER = 'TABLE_OWNER' -- replace with the owner AND TABLE_NAME = … free life insurance for disabled