WebPhysics questions and answers A 55 kg student is standing atop a spring in an elevator that is accelerating upward at 3.2 m/s2 . The spring constant is 2300 N/m . By how much is the spring compressed? This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer WebSep 29, 2005 · There are two forces acting on the elevator: The cable tension pulling up and the weight (mg) pulling down. Find the net upward force (in symbols) and set that equal to ma. Then you can solve for T. The second part of the equation says: The elevator now moves with a constant upward velocity of 10. Find T.
Why does the normal force go down in an downward accelerating eleva…
WebAt that height, the acceleration due to gravity has decreased to about 1% of the surface value. If we recall that work done is a force times a distance then we can see that … WebUsing both gravity and the so called centrifugal force, someone would feel .88 g's 250 miles up the elevator. At 22237 miles altitude I get -7.23 millionths of a g which is darn near … bark diagram
Elevators - Force and Power - Engineering ToolBox
WebGravity train. A gravity train is a theoretical means of transportation for purposes of commuting between two points on the surface of a sphere, by following a straight tunnel … WebAug 9, 2014 · Using the equation we found for elevators moving up: N UP = mg + ma = 100 kg At rest, the Normal force was N REST = mg = 75 kg Divide one equation into the other to find a ratio. a = 1 ⁄ 3 g The acceleration of the elevator is one third of a gravity. Since the acceleration is positive, the direction is up. WebDec 17, 2013 · Elevator Standing Still: Normal Force (reading on scale)= Weight of person = mg The Normal force required is enough to balance the downward force created by the mass (person) wanting to accelerate downward at 9.8 m/s/s. (the scale/floor of elevator prevents them from plummeting to their death) suzuki emiko